Optimal. Leaf size=349 \[ -\frac{b x^2 \text{PolyLog}\left (2,-\frac{a e^{c+d x^2}}{b-\sqrt{b^2-a^2}}\right )}{a d^2 \sqrt{b^2-a^2}}+\frac{b x^2 \text{PolyLog}\left (2,-\frac{a e^{c+d x^2}}{\sqrt{b^2-a^2}+b}\right )}{a d^2 \sqrt{b^2-a^2}}+\frac{b \text{PolyLog}\left (3,-\frac{a e^{c+d x^2}}{b-\sqrt{b^2-a^2}}\right )}{a d^3 \sqrt{b^2-a^2}}-\frac{b \text{PolyLog}\left (3,-\frac{a e^{c+d x^2}}{\sqrt{b^2-a^2}+b}\right )}{a d^3 \sqrt{b^2-a^2}}-\frac{b x^4 \log \left (\frac{a e^{c+d x^2}}{b-\sqrt{b^2-a^2}}+1\right )}{2 a d \sqrt{b^2-a^2}}+\frac{b x^4 \log \left (\frac{a e^{c+d x^2}}{\sqrt{b^2-a^2}+b}+1\right )}{2 a d \sqrt{b^2-a^2}}+\frac{x^6}{6 a} \]
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Rubi [A] time = 0.857936, antiderivative size = 349, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 8, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.444, Rules used = {5436, 4191, 3320, 2264, 2190, 2531, 2282, 6589} \[ -\frac{b x^2 \text{PolyLog}\left (2,-\frac{a e^{c+d x^2}}{b-\sqrt{b^2-a^2}}\right )}{a d^2 \sqrt{b^2-a^2}}+\frac{b x^2 \text{PolyLog}\left (2,-\frac{a e^{c+d x^2}}{\sqrt{b^2-a^2}+b}\right )}{a d^2 \sqrt{b^2-a^2}}+\frac{b \text{PolyLog}\left (3,-\frac{a e^{c+d x^2}}{b-\sqrt{b^2-a^2}}\right )}{a d^3 \sqrt{b^2-a^2}}-\frac{b \text{PolyLog}\left (3,-\frac{a e^{c+d x^2}}{\sqrt{b^2-a^2}+b}\right )}{a d^3 \sqrt{b^2-a^2}}-\frac{b x^4 \log \left (\frac{a e^{c+d x^2}}{b-\sqrt{b^2-a^2}}+1\right )}{2 a d \sqrt{b^2-a^2}}+\frac{b x^4 \log \left (\frac{a e^{c+d x^2}}{\sqrt{b^2-a^2}+b}+1\right )}{2 a d \sqrt{b^2-a^2}}+\frac{x^6}{6 a} \]
Antiderivative was successfully verified.
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Rule 5436
Rule 4191
Rule 3320
Rule 2264
Rule 2190
Rule 2531
Rule 2282
Rule 6589
Rubi steps
\begin{align*} \int \frac{x^5}{a+b \text{sech}\left (c+d x^2\right )} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{x^2}{a+b \text{sech}(c+d x)} \, dx,x,x^2\right )\\ &=\frac{1}{2} \operatorname{Subst}\left (\int \left (\frac{x^2}{a}-\frac{b x^2}{a (b+a \cosh (c+d x))}\right ) \, dx,x,x^2\right )\\ &=\frac{x^6}{6 a}-\frac{b \operatorname{Subst}\left (\int \frac{x^2}{b+a \cosh (c+d x)} \, dx,x,x^2\right )}{2 a}\\ &=\frac{x^6}{6 a}-\frac{b \operatorname{Subst}\left (\int \frac{e^{c+d x} x^2}{a+2 b e^{c+d x}+a e^{2 (c+d x)}} \, dx,x,x^2\right )}{a}\\ &=\frac{x^6}{6 a}-\frac{b \operatorname{Subst}\left (\int \frac{e^{c+d x} x^2}{2 b-2 \sqrt{-a^2+b^2}+2 a e^{c+d x}} \, dx,x,x^2\right )}{\sqrt{-a^2+b^2}}+\frac{b \operatorname{Subst}\left (\int \frac{e^{c+d x} x^2}{2 b+2 \sqrt{-a^2+b^2}+2 a e^{c+d x}} \, dx,x,x^2\right )}{\sqrt{-a^2+b^2}}\\ &=\frac{x^6}{6 a}-\frac{b x^4 \log \left (1+\frac{a e^{c+d x^2}}{b-\sqrt{-a^2+b^2}}\right )}{2 a \sqrt{-a^2+b^2} d}+\frac{b x^4 \log \left (1+\frac{a e^{c+d x^2}}{b+\sqrt{-a^2+b^2}}\right )}{2 a \sqrt{-a^2+b^2} d}+\frac{b \operatorname{Subst}\left (\int x \log \left (1+\frac{2 a e^{c+d x}}{2 b-2 \sqrt{-a^2+b^2}}\right ) \, dx,x,x^2\right )}{a \sqrt{-a^2+b^2} d}-\frac{b \operatorname{Subst}\left (\int x \log \left (1+\frac{2 a e^{c+d x}}{2 b+2 \sqrt{-a^2+b^2}}\right ) \, dx,x,x^2\right )}{a \sqrt{-a^2+b^2} d}\\ &=\frac{x^6}{6 a}-\frac{b x^4 \log \left (1+\frac{a e^{c+d x^2}}{b-\sqrt{-a^2+b^2}}\right )}{2 a \sqrt{-a^2+b^2} d}+\frac{b x^4 \log \left (1+\frac{a e^{c+d x^2}}{b+\sqrt{-a^2+b^2}}\right )}{2 a \sqrt{-a^2+b^2} d}-\frac{b x^2 \text{Li}_2\left (-\frac{a e^{c+d x^2}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{b x^2 \text{Li}_2\left (-\frac{a e^{c+d x^2}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{b \operatorname{Subst}\left (\int \text{Li}_2\left (-\frac{2 a e^{c+d x}}{2 b-2 \sqrt{-a^2+b^2}}\right ) \, dx,x,x^2\right )}{a \sqrt{-a^2+b^2} d^2}-\frac{b \operatorname{Subst}\left (\int \text{Li}_2\left (-\frac{2 a e^{c+d x}}{2 b+2 \sqrt{-a^2+b^2}}\right ) \, dx,x,x^2\right )}{a \sqrt{-a^2+b^2} d^2}\\ &=\frac{x^6}{6 a}-\frac{b x^4 \log \left (1+\frac{a e^{c+d x^2}}{b-\sqrt{-a^2+b^2}}\right )}{2 a \sqrt{-a^2+b^2} d}+\frac{b x^4 \log \left (1+\frac{a e^{c+d x^2}}{b+\sqrt{-a^2+b^2}}\right )}{2 a \sqrt{-a^2+b^2} d}-\frac{b x^2 \text{Li}_2\left (-\frac{a e^{c+d x^2}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{b x^2 \text{Li}_2\left (-\frac{a e^{c+d x^2}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{b \operatorname{Subst}\left (\int \frac{\text{Li}_2\left (\frac{a x}{-b+\sqrt{-a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x^2}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{b \operatorname{Subst}\left (\int \frac{\text{Li}_2\left (-\frac{a x}{b+\sqrt{-a^2+b^2}}\right )}{x} \, dx,x,e^{c+d x^2}\right )}{a \sqrt{-a^2+b^2} d^3}\\ &=\frac{x^6}{6 a}-\frac{b x^4 \log \left (1+\frac{a e^{c+d x^2}}{b-\sqrt{-a^2+b^2}}\right )}{2 a \sqrt{-a^2+b^2} d}+\frac{b x^4 \log \left (1+\frac{a e^{c+d x^2}}{b+\sqrt{-a^2+b^2}}\right )}{2 a \sqrt{-a^2+b^2} d}-\frac{b x^2 \text{Li}_2\left (-\frac{a e^{c+d x^2}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{b x^2 \text{Li}_2\left (-\frac{a e^{c+d x^2}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^2}+\frac{b \text{Li}_3\left (-\frac{a e^{c+d x^2}}{b-\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}-\frac{b \text{Li}_3\left (-\frac{a e^{c+d x^2}}{b+\sqrt{-a^2+b^2}}\right )}{a \sqrt{-a^2+b^2} d^3}\\ \end{align*}
Mathematica [A] time = 1.48106, size = 376, normalized size = 1.08 \[ \frac{-6 b e^c d x^2 \text{PolyLog}\left (2,-\frac{a e^{2 c+d x^2}}{b e^c-\sqrt{e^{2 c} \left (b^2-a^2\right )}}\right )+6 b e^c d x^2 \text{PolyLog}\left (2,-\frac{a e^{2 c+d x^2}}{\sqrt{e^{2 c} \left (b^2-a^2\right )}+b e^c}\right )+6 b e^c \text{PolyLog}\left (3,-\frac{a e^{2 c+d x^2}}{b e^c-\sqrt{e^{2 c} \left (b^2-a^2\right )}}\right )-6 b e^c \text{PolyLog}\left (3,-\frac{a e^{2 c+d x^2}}{\sqrt{e^{2 c} \left (b^2-a^2\right )}+b e^c}\right )+d^3 x^6 \sqrt{e^{2 c} \left (b^2-a^2\right )}-3 b e^c d^2 x^4 \log \left (\frac{a e^{2 c+d x^2}}{b e^c-\sqrt{e^{2 c} \left (b^2-a^2\right )}}+1\right )+3 b e^c d^2 x^4 \log \left (\frac{a e^{2 c+d x^2}}{\sqrt{e^{2 c} \left (b^2-a^2\right )}+b e^c}+1\right )}{6 a d^3 \sqrt{e^{2 c} \left (b^2-a^2\right )}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.053, size = 0, normalized size = 0. \begin{align*} \int{\frac{{x}^{5}}{a+b{\rm sech} \left (d{x}^{2}+c\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 2.32902, size = 1670, normalized size = 4.79 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{5}}{a + b \operatorname{sech}{\left (c + d x^{2} \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{5}}{b \operatorname{sech}\left (d x^{2} + c\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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